What about General Relativity GR?

Argument #1

LIF is same result as below for SR. Use the EQUIVALENCE PRINCIPLE tetrad transformation e^au to go from 1905 SR LIF to LOCALLY COINCIDENT 1916 LNIF. A GCT scalar invariant remains an invariant. For example, given a first rank LIF tensor Ta (LIF) then Tu(LNIF) = eu^aTa, but a LIF scalar has no LIF "a-indices" therefore the scalar remains a scalar.

But is the above really correct? Remember, the Unruh effect

http://en.wikipedia.org/wiki/Unruh_effect

(~ Black Hole temperature, entropy & Hawking radiation) tetrad map LIF -> LNIF = accelerated non-inertial frame off-curved spacetime geodesic, hence g-forces (universal weight) and according to Unruh a black body temperature depending on the actual off-geodesic acceleration caused by a non-gravity translational force and/or a conserved orbital angular momentum in vacuum. Temperature ~ surface gravity in case of event horizon of a black hole.

http://en.wikipedia.org/wiki/Black_hole_thermodynamics

Begin forwarded message:

From: physnews@aip.org

Date: October 18, 2007 8:46:43 AM PDT

To: sarfatti@well.com

Subject: Physics News Update 843

Reply-To: physnews@aip.org

PHYSICS NEWS UPDATE

The American Institute of Physics Bulletin of Physics News

Number 843 October 18, 2007 by Phillip F. Schewe

www.aip.org/pnu

RELATIVISTIC THERMODYNAMICS. Einstein*s special theory of

relativity has formulas, called Lorentz transformations, that

convert time or distance intervals from a resting frame of reference

to a frame zooming by at nearly the speed of light. But how about

temperature? That is, if a speeding observer, carrying her

thermometer with her, tries to measure the temperature of a gas in a

stationary bottle, what temperature will she measure? A new look at

this contentious subject suggests that the temperature will be the

same as that measured in the rest frame. In other words, moving

bodies will not appear hotter or colder.

You*d think that such an issue would have been settled decades ago,

but this is not the case. Einstein and Planck thought, at one time,

that the speeding thermometer would measure a lower temperature,

while others thought the temperature would be higher. One problem

is how to define or measure a gas temperature in the first place.

James Clerk Maxwell in 1866 enunciated his famous formula predicting

that the distribution of gas particle velocities would look like a

Gaussian-shaped curve. But how would this curve appear to be for

someone flying past? What would the equivalent average gas

temperature be to this other observer? Jorn Dunkel and his

colleagues at the Universitat Augsburg (Germany) and the Universidad

de Sevilla (Spain) could not exactly make direct measurements (no

one has figured out how to maintain a contained gas at relativistic

speeds in a terrestrial lab), but they performed extensive

simulations of the matter. Dunkel

(joern.dunkel@physik.uni-augsburg.de ) says that some astrophysical

systems might eventually offer a chance to experimentally judge the

issue. In general the effort to marry thermodynamics with special

relativity is still at an early stage. It is not exactly known how

several thermodynamic parameters change at high speeds. Absolute

zero, Dunkel says, will always be absolute zero, even for

quickly-moving observers. But producing proper Lorentz

transformations for other quantities such as entropy will be

trickier to do. (Cubero et al., Physical Review Letters, 26 October

2007; text available to journalists at www.aip.org/physnews/select)

## Thursday, October 18, 2007

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